< 0cm 0cm 0pt"><FONT face="Times New Roman"> (a)<p></p></FONT></P>< 0cm 0cm 0pt; TEXT-INDENT: 48pt; mso-char-indent-count: 4.0; mso-char-indent-size: 12.0pt"><FONT face="Times New Roman">2 6 1 4 3<p></p></FONT></P>< 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> <p></p></FONT></P><BR vglayout" clear=all><P 0cm 0cm 0pt"><FONT face="Times New Roman">(b)<p></p></FONT></P><P 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> 2 14<p></p></FONT></P><P 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> <p></p></FONT></P><BR vglayout" clear=all><P 0cm 0cm 0pt"><FONT face="Times New Roman"> 8 8<p></p></FONT></P><P 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> <p></p></FONT></P><BR vglayout" clear=all><P 0cm 0cm 0pt"><FONT face="Times New Roman"> 9 7<p></p></FONT></P><P 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> <p></p></FONT></P><BR vglayout" clear=all><P 0cm 0cm 0pt"><FONT face="Times New Roman"> 13 3<p></p></FONT></P><P 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> <p></p></FONT></P><BR vglayout" clear=all><P 0cm 0cm 0pt"><FONT face="Times New Roman"> <p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 48pt; mso-char-indent-count: 4.0; mso-char-indent-size: 12.0pt"><FONT face="Times New Roman">2 1 4 3 6<p></p></FONT></P><P 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> <p></p></FONT></P><P 0cm 0cm 0pt"><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><v:line><FONT face="Times New Roman"></FONT></v:line><FONT face="Times New Roman"> <p></p></FONT></P><BR vglayout" clear=all><P 0cm 0cm 0pt; TEXT-INDENT: 31.5pt; mso-char-indent-count: 3.0; mso-char-indent-size: 10.5pt">图<FONT face="Times New Roman">2. </FONT>这个例子对应的位点有<FONT face="Times New Roman">4</FONT>个。<FONT face="Times New Roman">(a) </FONT>就是我们希望重构的顺序。<FONT face="Times New Roman"> (b)</FONT>中的前<FONT face="Times New Roman">4</FONT>对为第一组数据,它通过切开一个位点得到,每对长度的和都是<FONT face="Times New Roman">16</FONT>,剩下的为第二组数据,含<FONT face="Times New Roman">5</FONT>个片段长度,它通过切开所有位点得到,它们的长度总和也是<FONT face="Times New Roman">16</FONT>,<FONT face="Times New Roman"> </FONT>但实验结果只告知每段的长度,不知道它们在<FONT face="Times New Roman">DNA</FONT>分子上的排列顺序。<p></p></P><P 0cm 0cm 0pt"><FONT face="Times New Roman"> <p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">现对上述<FONT face="Times New Roman">SPDP</FONT>问题,建立数学模型,并研究以下问题:<p></p></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">设计求解该问题的算法,<FONT face="Times New Roman"> </FONT>并评估该算法的效率和效果。对下述<FONT face="Times New Roman">2</FONT>个实例给出答案:<p></p></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">实例<FONT face="Times New Roman">1</FONT>:<FONT face="Times New Roman"> <p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">第一组数据:<FONT face="Times New Roman">2</FONT>,<FONT face="Times New Roman">14</FONT>,<FONT face="Times New Roman">8</FONT>,<FONT face="Times New Roman">8</FONT>,<FONT face="Times New Roman">9</FONT>,<FONT face="Times New Roman">7</FONT>,<FONT face="Times New Roman">13</FONT>,<FONT face="Times New Roman">3 <p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">第二组数据:<FONT face="Times New Roman">2</FONT>,<FONT face="Times New Roman">1</FONT>,<FONT face="Times New Roman">4</FONT>,<FONT face="Times New Roman">3</FONT>,<FONT face="Times New Roman">6<p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">实例<FONT face="Times New Roman">2: <p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">第一组数据:<FONT face="Times New Roman">1</FONT>,<FONT face="Times New Roman">14</FONT>,<FONT face="Times New Roman">12</FONT>,<FONT face="Times New Roman">3</FONT>,<FONT face="Times New Roman">7</FONT>,<FONT face="Times New Roman">8</FONT>,<FONT face="Times New Roman">9</FONT>,<FONT face="Times New Roman">6</FONT>,<FONT face="Times New Roman">11</FONT>,<FONT face="Times New Roman">4</FONT>,<FONT face="Times New Roman">12</FONT>,<FONT face="Times New Roman">3</FONT>,<FONT face="Times New Roman">13</FONT>,<FONT face="Times New Roman">2</FONT>,<FONT face="Times New Roman">5</FONT>,<FONT face="Times New Roman">10<p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">第二组数据:<FONT face="Times New Roman">1</FONT>,<FONT face="Times New Roman">1</FONT>,<FONT face="Times New Roman">2</FONT>,<FONT face="Times New Roman">1</FONT>,<FONT face="Times New Roman">2</FONT>,<FONT face="Times New Roman">2</FONT>,<FONT face="Times New Roman">1</FONT>,<FONT face="Times New Roman">2</FONT>,<FONT face="Times New Roman">3<p></p></FONT></P><P 0cm 0cm 0pt"><FONT face="Times New Roman"> <p></p></FONT></P><P 0cm 0cm 0pt; TEXT-INDENT: 22pt; mso-char-indent-count: 2.0; mso-char-indent-size: 11.0pt">讨论在实验中测量片段长度时的误差,将在多大程度上影响算法的效果,当误差到多大程度时,限制性图谱的重构将无法进行。<p></p></P>