[SOS]有哪位GS会用LINGO的整数规划啊!!

infant · 发表于 2004-8-30 04:36:09

<

>LINGO 8的整数规划怎么样表示啊.源程序如下
<

>min=f11+f12+f13+f21+f22+f23+f31+f32+f33+fa11+fa12+fa13+fa21+fa22+fa23+fa31+fa32+fa33;
0.75*x11+0.5*a11-s11-f11-fa11+0.5*du11+0.5*du12=-800;
0.8*x12+0.5*a12-s12-f12-fa12-du11+0.5*du13=-25;
0.9*x13+0.5*a13-s13-f13-du12-du13=50;
0.75*x21-p11+0.5*a21-s21-f21-fa21+0.5*du21+0.5*du22=-400;
0.8*x22-p12+p11+0.5*a22-s22-f22-fa22-du21+0.5*du23=575;
0.9*x23+p12+0.5*a23-s23-f23-du22-du23=550;
0.75*x31-p21+0.5*a31-s31-f31-fa31+0.5*du31+0.5*du32=-450;
0.8*x32+p21-p22+0.5*a32+s32-f32-fa32-du31+0.5*du33=600;
0.9*x33+p22+0.5*a33-s33-f33-du32-du33=575;
s11+s12+s13<=150;
s21+s22+s23<=150;
s31+s32+s33<=150;
a11<=50;
a12<=50;
a13<=50;
x11<=800;
x12<=500;
x13<=800;
a21<=50;
a22<=50;
a23<=50;
x21<=800;
x22<=500;
x23<=800;
x31<=800;
x32<=500;
x33<=800;
p11<=200;
p21<=200;
p12-0.25*x13<=0;
p22-0.25*x23<=0;
end 
<

>解出来的不是整数,整数要怎样表示啊...SOS啊

meng8kun · 发表于 2004-8-30 20:31:30

<

>在后面加类似于下面的语句：<

>@gin(x11)

infant · 发表于 2004-8-30 23:08:14

<

>可以了,谢谢......^_^
<

>不过有可以一个函数或者一两句话表示全部变量都是整数的吗?用@gin(x11)这样只能够表示其中一个x11是整数啊.全部变量都是整数要怎么表示啊....谢谢先咯.

163er · 发表于 2004-8-31 07:50:38

<

>没有充分利用lingo内置的建模语言，好像无法对索引集合内循环。

pathfinder · 发表于 2004-8-31 16:55:23

<

>不过有可以一个函数或者一两句话表示全部变量都是整数的吗?用@gin(x11)这样只能够表示其中一个x11是整数啊.全部变量都是整数要怎么表示啊....谢谢先咯.<

> 可以用lindo啊<

>只要在后面加上int 30（30为变量数）就行了

sghmk · 发表于 2004-9-2 19:42:11

先定义集，那样就可以用一个函数表达了

hongming6662 · 发表于 2004-9-4 03:31:36

<

>LP OPTIMUM FOUND AT STEP 7<

> OBJECTIVE FUNCTION VALUE<

> 1) 812.5000 VARIABLE VALUE REDUCED COST
 F11 0.000000 0.000000
 F12 0.000000 0.500000
 F13 0.000000 1.000000
 F21 0.000000 0.000000
 F22 0.000000 1.000000
 F23 0.000000 1.000000
 F31 0.000000 0.000000
 F32 0.000000 1.000000
 F33 0.000000 1.000000
 FA11 662.500000 0.000000
 FA12 0.000000 0.500000
 FA13 0.000000 1.000000
 FA21 50.000000 0.000000
 FA22 0.000000 1.000000
 FA23 0.000000 1.000000
 FA31 100.000000 0.000000
 FA32 0.000000 1.000000
 FA33 0.000000 1.000000
 X11 0.000000 0.750000
 A11 0.000000 0.500000
 S11 150.000000 0.000000
 DU11 25.000000 0.000000
 DU12 0.000000 0.500000
 X12 0.000000 0.400000
 A12 0.000000 0.250000
 S12 0.000000 0.500000
 DU13 0.000000 0.250000
 X13 55.555557 0.000000
 A13 0.000000 0.000000
 S13 0.000000 1.000000
 X21 0.000000 0.750000
 P11 200.000000 0.000000
 A21 0.000000 0.500000
 S21 150.000000 0.000000
 DU21 0.000000 0.500000
 DU22 0.000000 0.500000
 X22 371.180542 0.000000
 P12 13.888889 0.000000
 A22 0.000000 0.000000
 S22 0.000000 1.000000
 DU23 183.888885 0.000000
 X23 800.000000 0.000000
 A23 0.000000 0.000000
 S23 0.000000 1.000000
 X31 0.000000 0.750000
 P21 200.000000 0.000000
 A31 0.000000 0.500000
 S31 150.000000 0.000000
 DU31 0.000000 0.500000
 DU32 0.000000 0.500000
 X32 0.000000 0.000000
 P22 0.000000 0.000000
 A32 800.000000 0.000000
 S32 0.000000 1.000000
 DU33 0.000000 0.000000
 X33 0.000000 0.000000
 A33 1150.000000 0.000000
 S33 0.000000 1.000000

hongming6662 · 发表于 2004-9-4 03:39:41

min f11+f12+f13+f21+f22+f23+f31+f32+f33+fa11+fa12+fa13+fa21+fa22+fa23+fa31+fa32+fa33
subject to
0.75x11+0.5a11-s11-f11-fa11+0.5du11+0.5du12=-800
0.8x12+0.5a12-s12-f12-fa12-du11+0.5du13=-25
0.9x13+0.5a13-s13-f13-du12-du13=50
0.75x21-p11+0.5a21-s21-f21-fa21+0.5du21+0.5du22=-400
0.8x22-p12+p11+0.5a22-s22-f22-fa22-du21+0.5du23=575
0.9x23+p12+0.5a23-s23-f23-du22-du23=550
0.75x31-p21+0.5a31-s31-f31-fa31+0.5du31+0.5du32=-450
0.8x32+p21-p22+0.5a32+s32-f32-fa32-du31+0.5du33=600
0.9x33+p22+0.5a33-s33-f33-du32-du33=575
s11+s12+s13<=150
s21+s22+s23<=150
s31+s32+s33<=150
a11<=50
a12<=50
a13<=50
x11<=800
x12<=500
x13<=800
a21<=50
a22<=50
a23<=50
x21<=800
x22<=500
x23<=800
x31<=800
x32<=500
x33<=800
p11<=200
p21<=200
p12-0.25x13<=0
p22-0.25x23<=0
end
gin 30

海之子 · 发表于 2004-9-5 00:13:58

<

>如果有30个变量的话，如果你想定义这30个变两都是整数的话就用 gin（30）；<

>如果是前12个就用gin（12）就可以了<

>当然用上面的方法也行

lwd1981 · 发表于 2004-9-11 02:25:57

好啊!

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