关于LINGO整数规划

11韩中英ty · 发表于 2005-9-9 17:17:54

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>请教大家一个问题：在LINGO软件中怎样将结果整数化？
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>例如：model: Max =48.7*(x1+y1)+52*(x2+y2)+61.3*(x3+y3)+72*(x4+y4)+48.7*(x5+y5)+52*(x6+y6)+64*(x7+y7); 48.7*x1+52*x2+61.3*x3+72*x4+48.7*x5+52*x6+64*x7<=1020; 48.7*y1+52*y2+61.3*y3+72*y4+48.7*y5+52*y6+64*y7<=1020; 2*x1+3*x2+1*x3+0.5*x4+4*x5+2*x6+1*x7<=40; 2*y1+3*y2+1*y3+0.5*y4+4*y5+2*y6+1*y7<=40; x1+y1<=8; x2+y2<=7; x3+y3<=9; x4+y4<=6; x5+y5<=6; x6+y6<=4; x7+y7<=8; 48.7*(x5+y5)+52*(x6+y6)+64*(x7+y7)<=302.7; x1>=0; x2>=0; x3>=0; x4>=0; x5>=0; x6>=0; x7>=0; y1>=0; y2>=0; y3>=0; y4>=0; y5>=0; y6>=0; y7>=0;
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>想要结果整数化，输入怎样的程序？？？？？
多多感谢！！！！

beezh · 发表于 2005-9-9 21:16:47

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>加入下列语句即可:
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>@gin(x1); @gin(x2); @gin(x3); @gin(x4); @gin(x5); @gin(x6); @gin(x7); @gin(y1); @gin(y2); @gin(y3); @gin(y4); @gin(y5); @gin(y6); @gin(y7); 
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>(LZ写的LINGO程序太麻烦了 ~~)[em07][em07]

金国洪 · 发表于 2005-9-9 22:25:18

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>Global optimal solution found at iteration: 7 Objective value: 2040.000
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> Variable Value Reduced Cost X1 8.000000 0.000000 Y1 0.000000 0.000000 X2 6.374526 0.000000 Y2 0.6254738 0.000000 X3 4.876422 0.000000 Y3 4.123578 0.000000 X4 0.000000 0.000000 Y4 6.000000 0.000000 X5 0.000000 0.000000 Y5 0.000000 0.000000 X6 0.000000 0.000000 Y6 0.000000 0.000000 X7 0.000000 0.000000 Y7 4.729687 0.000000 MAX 0.000000 0.000000
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> Row Slack or Surplus Dual Price 1 2040.000 1.000000 2 0.000000 0.000000 3 0.000000 0.000000 4 0.000000 0.000000 5 26.27031 0.000000 6 0.000000 48.70000 7 0.000000 52.00000 8 0.000000 61.30000 9 0.000000 72.00000 10 6.000000 0.000000 11 4.000000 0.000000 12 3.270313 0.000000 13 0.000000 1.000000 14 8.000000 0.000000 15 6.374526 0.000000 16 4.876422 0.000000 17 0.000000 0.000000 18 0.000000 0.000000 19 0.000000 0.000000 20 0.000000 0.000000 21 0.000000 0.000000 22 0.6254738 0.000000 23 4.123578 0.000000 24 6.000000 0.000000 25 0.000000 0.000000 26 0.000000 0.000000 27 4.729687 0.000000
请问结果是不是这样的啊

beezh · 发表于 2005-9-10 17:17:22

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>是这样:
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> Global optimal solution found at iteration: 174785 Objective value: 2039.400
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> Variable Value Reduced Cost X1 4.000000 -48.70000 Y1 4.000000 -48.70000 X2 7.000000 -52.00000 Y2 0.000000 -52.00000 X3 0.000000 -61.30000 Y3 9.000000 -61.30000 X4 5.000000 -72.00000 Y4 1.000000 -72.00000 X5 1.000000 -48.70000 Y5 2.000000 -48.70000 X6 1.000000 -52.00000 Y6 2.000000 -52.00000 X7 0.000000 -64.00000 Y7 0.000000 -64.00000
 Row Slack or Surplus Dual Price 1 2039.400 1.000000 2 0.5000000 0.000000 3 0.1000000 0.000000 4 2.500000 0.000000 5 10.50000 0.000000 6 0.000000 0.000000 7 0.000000 0.000000 8 0.000000 0.000000 9 0.000000 0.000000 10 3.000000 0.000000 11 1.000000 0.000000 12 8.000000 0.000000 13 0.6000000 0.000000 14 4.000000 0.000000 15 7.000000 0.000000 16 0.000000 0.000000 17 5.000000 0.000000 18 1.000000 0.000000 19 1.000000 0.000000 20 0.000000 0.000000 21 4.000000 0.000000 22 0.000000 0.000000 23 9.000000 0.000000 24 1.000000 0.000000 25 2.000000 0.000000 26 2.000000 0.000000 27 0.000000 0.000000
[em01][em01]

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