工件检测问题

淡月如钩 · 发表于 2005-5-5 17:38:57

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align=left>请高手给点思路：
<

align=left> 
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>某工件为圆形, 半径为<st1:chmetcnv w:st="on" TCSC="0" NumberType="1" Negative="False" HasSpace="False" SourceValue="10" UnitName="mm">10mm</st1:chmetcnv><v:shapetype> <v:stroke joinstyle="miter"></v:stroke><v:formulas><v:f eqn="if lineDrawn pixelLineWidth 0"></v:f><v:f eqn="sum @0 1 0"></v:f><v:f eqn="sum 0 0 @1"></v:f><v:f eqn="prod @2 1 2"></v:f><v:f eqn="prod @3 21600 pixelWidth"></v:f><v:f eqn="prod @3 21600 pixelHeight"></v:f><v:f eqn="sum @0 0 1"></v:f><v:f eqn="prod @6 1 2"></v:f><v:f eqn="prod @7 21600 pixelWidth"></v:f><v:f eqn="sum @8 21600 0"></v:f><v:f eqn="prod @7 21600 pixelHeight"></v:f><v:f eqn="sum @10 21600 0"></v:f></v:formulas><v:path gradientshapeok="t" extrusionok="f" connecttype="rect"></v:path><LOCK aspectratio="t" v:ext="edit"></LOCK></v:shapetype><v:shape><v:imagedata></v:imagedata></v:shape><st1:chmetcnv w:st="on" TCSC="0" NumberType="1" Negative="False" HasSpace="False" SourceValue=".1" UnitName="mm">0.1mm</st1:chmetcnv>, 超出此范围即为次品. 测量仪器自动在每个工件的圆周上测量36个数据. 假定测量出的二维数据 (<v:shape> <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata></v:imagedata></v:shape>) 是足够精确的, 要求建立一个合理的检验正/次品的模型, 对每个工件的36个数据进行计算后给出判断。


 
下面是5个工件的测量文件, 存放顺序为
((<v:shape> x11<v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y11</v:imagedata></v:shape>)，(<v:shape>x12 <v:imagedata></v:imagedata></v:shape>, <v:shape>
<v:imagedata></v:imagedata> 
<v:imagedata>y12</v:imagedata></v:shape>)，……，(<v:shape>x1,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y1,36</v:imagedata></v:shape>)
(<v:shape>x21 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y21</v:imagedata></v:shape>)，(<v:shape>x22 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y22</v:imagedata></v:shape>)，……，(<v:shape>x2,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y2,36</v:imagedata></v:shape>)
(<v:shape>x31 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y31</v:imagedata></v:shape>)，(<v:shape>x32 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y32</v:imagedata></v:shape>)，……，(<v:shape>x3,36 <v:imagedata></v:imagedata></v:shape>, y3,36)
(<v:shape>x41 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y41</v:imagedata></v:shape>)，(<v:shape>x42 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y42</v:imagedata></v:shape>)，……，(<v:shape>x4,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y4,36</v:imagedata></v:shape>)
(<v:shape>x51 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y51</v:imagedata></v:shape>)，(<v:shape>x52 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y52</v:imagedata></v:shape>)，……，(<v:shape>x5,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y5,36</v:imagedata></v:shape>)

其中(xi<v:shape> j<v:imagedata></v:imagedata></v:shape>,yij <v:shape><v:imagedata></v:imagedata></v:shape>)表示第<v:shape> i<v:imagedata></v:imagedata></v:shape>个工件第<v:shape> j<v:imagedata></v:imagedata></v:shape>个测量数据 (1.<v:shape> <v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape>5, 1<v:shape> <v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape>36)。如第一个工件中 <v:shape><v:imagedata></v:imagedata></v:shape>= 31.270, <v:shape><v:imagedata></v:imagedata></v:shape>= 34.290, <v:shape><v:imagedata></v:imagedata></v:shape>= 31.227, <v:shape><v:imagedata></v:imagedata></v:shape>= 36.554, ……, <v:shape><v:imagedata></v:imagedata></v:shape>= 30.964, <v:shape><v:imagedata></v:imagedata></v:shape>= 31.517, <v:shape><v:imagedata></v:imagedata></v:shape>= 31.105, <v:shape><v:imagedata></v:imagedata></v:shape>= 32.743。

[此贴子已经被作者于2005-5-5 9:46:43编辑过]

我不爱数学 · 发表于 2005-8-2 18:33:08

试用假设检验给出拒绝域看看

shirxy · 发表于 2005-8-30 23:38:13

<DIV class=quote>以下是引用淡月如钩在2005-5-5 9:38:57的发言： 
<

align=left>请高手给点思路：
<

align=left> 
<

>某工件为圆形, 半径为<st1:chmetcnv UnitName="mm" SourceValue="10" HasSpace="False" Negative="False" NumberType="1" TCSC="0" w:st="on">10mm</st1:chmetcnv><v:shapetype> <v:stroke joinstyle="miter"></v:stroke><v:formulas><v:f eqn="if lineDrawn pixelLineWidth 0"></v:f><v:f eqn="sum @0 1 0"></v:f><v:f eqn="sum 0 0 @1"></v:f><v:f eqn="prod @2 1 2"></v:f><v:f eqn="prod @3 21600 pixelWidth"></v:f><v:f eqn="prod @3 21600 pixelHeight"></v:f><v:f eqn="sum @0 0 1"></v:f><v:f eqn="prod @6 1 2"></v:f><v:f eqn="prod @7 21600 pixelWidth"></v:f><v:f eqn="sum @8 21600 0"></v:f><v:f eqn="prod @7 21600 pixelHeight"></v:f><v:f eqn="sum @10 21600 0"></v:f></v:formulas><v:path connecttype="rect" extrusionok="f" gradientshapeok="t"></v:path><LOCK v:ext="edit" aspectratio="t"></LOCK></v:shapetype><v:shape><v:imagedata></v:imagedata></v:shape><st1:chmetcnv UnitName="mm" SourceValue=".1" HasSpace="False" Negative="False" NumberType="1" TCSC="0" w:st="on">0.1mm</st1:chmetcnv>, 超出此范围即为次品. 测量仪器自动在每个工件的圆周上测量36个数据. 假定测量出的二维数据 (<v:shape> <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata></v:imagedata></v:shape>) 是足够精确的, 要求建立一个合理的检验正/次品的模型, 对每个工件的36个数据进行计算后给出判断。

 
下面是5个工件的测量文件, 存放顺序为
((<v:shape> x11<v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y11</v:imagedata></v:shape>)，(<v:shape>x12 <v:imagedata></v:imagedata></v:shape>, <v:shape>
<v:imagedata></v:imagedata>
<v:imagedata>y12</v:imagedata></v:shape>)，……，(<v:shape>x1,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y1,36</v:imagedata></v:shape>)
 
(<v:shape>x21 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y21</v:imagedata></v:shape>)，(<v:shape>x22 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y22</v:imagedata></v:shape>)，……，(<v:shape>x2,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y2,36</v:imagedata></v:shape>)
(<v:shape>x31 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y31</v:imagedata></v:shape>)，(<v:shape>x32 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y32</v:imagedata></v:shape>)，……，(<v:shape>x3,36 <v:imagedata></v:imagedata></v:shape>, y3,36)
(<v:shape>x41 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y41</v:imagedata></v:shape>)，(<v:shape>x42 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y42</v:imagedata></v:shape>)，……，(<v:shape>x4,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y4,36</v:imagedata></v:shape>)
(<v:shape>x51 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y51</v:imagedata></v:shape>)，(<v:shape>x52 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y52</v:imagedata></v:shape>)，……，(<v:shape>x5,36 <v:imagedata></v:imagedata></v:shape>, <v:shape><v:imagedata>y5,36</v:imagedata></v:shape>)

其中(xi<v:shape> j<v:imagedata></v:imagedata></v:shape>,yij <v:shape><v:imagedata></v:imagedata></v:shape>)表示第<v:shape> i<v:imagedata></v:imagedata></v:shape>个工件第<v:shape> j<v:imagedata></v:imagedata></v:shape>个测量数据 (1.<v:shape> <v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape>5, 1<v:shape> <v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape><v:shape><v:imagedata></v:imagedata></v:shape>36)。如第一个工件中 <v:shape><v:imagedata></v:imagedata></v:shape>= 31.270, <v:shape><v:imagedata></v:imagedata></v:shape>= 34.290, <v:shape><v:imagedata></v:imagedata></v:shape>= 31.227, <v:shape><v:imagedata></v:imagedata></v:shape>= 36.554, ……, <v:shape><v:imagedata></v:imagedata></v:shape>= 30.964, <v:shape><v:imagedata></v:imagedata></v:shape>= 31.517, <v:shape><v:imagedata></v:imagedata></v:shape>= 31.105, <v:shape><v:imagedata></v:imagedata></v:shape>= 32.743。
 </DIV>

eaglelhz · 发表于 2005-9-4 23:17:05

<

>你看看苏北竞赛论文就会了

badger · 发表于 2009-5-11 21:45:58

哪有苏北竞赛论文？

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工件检测问题

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