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LINGO8.0 for windows软件及应用(编译)

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发表于 2007-1-17 23:04:21 | 显示全部楼层
liuziqiang7@sohu.com
发表于 2007-3-13 00:04:20 | 显示全部楼层
<p>请发到<a href="mailto:li201599@yahoo.com.cn">li201599@yahoo.com.cn</a>&nbsp;&nbsp; 麻烦了</p>
发表于 2007-3-19 09:03:57 | 显示全部楼层

我想要一份

<p>我的邮箱是<a href="mailto:khejing3@yahoo.com.cn">khejing3@yahoo.com.cn</a></p><p>可以说是急需了,也不知道现在还发不发.总之谢谢了.</p>
发表于 2007-4-6 03:30:02 | 显示全部楼层
<p>MODEL:<br/>SETS:<br/>venders1/v1,v2/:c1,x1;<br/>goods1/g1,g2/:h1,i1,m1,o1;<br/>vg1(venders1,goods1):q1,d1,z1,g1,b1,p1;<br/>venders2/s1,s2/:c2,x2;<br/>goods2/w1,w2/:h2,i2,m2,o2;<br/>vg2(Venders2,goods2):q2,d2,z2,g2,b2,p2;<br/>ENDSETS<br/>DATA:<br/>c1= 1200,2000;<br/>h1= 1,1.5;<br/>m1= 3500,4000;<br/>q1= 0.04 0.02<br/>&nbsp;&nbsp;&nbsp; 0.03 0.04;<br/>d1= 0.18 0.09<br/>&nbsp;&nbsp;&nbsp; 0.2 0.1;<br/>g1= 2 1.8<br/>&nbsp;&nbsp;&nbsp; 1 0.8;<br/>b1= 3000 5000<br/>&nbsp;&nbsp;&nbsp; 3000 4000;<br/>p1= 5 5.1<br/>&nbsp;&nbsp;&nbsp; 2.2 2.1;<br/>c2= 1200,2000;<br/>h2= 1,1.5;<br/>m2= 3200,3500;<br/>q2= 0.04 0.02<br/>&nbsp;&nbsp;&nbsp; 0.03 0.04;<br/>d2= 0.18 0.09<br/>&nbsp;&nbsp;&nbsp; 0.2 0.1;<br/>G2= 2 1.8<br/>&nbsp;&nbsp;&nbsp; 1 0.8;<br/>b2= 3500 4500<br/>&nbsp;&nbsp;&nbsp; 3000 4000;<br/>p2= 5 5.1<br/>&nbsp;&nbsp;&nbsp; 2.2 2.1;</p><p>o1=100,80;</p><p>o2=100,80;<br/>i1= 0,0;<br/>ENDDATA<br/><a href="mailto:min=@sum(vg1(I,J)1(I,J)*z1(I,J))+@sum(venders1:x1*c1)+@sum(vg1(i,j):g1(i,j)*z1(i,j))+@sum(goods1:h1*i1)+@sum(vg2(i,j)2(i,j)*z2(i,j))+@sum(venders2:x2*c2)+@sum(vg2(i,j):g2(i,j)*z2(i,j)+@sum(goods2:h2*i2" target="_blank"><font color="#000000">min=@sum(vg1(I,J)1(I,J)*z1(I,J))+@sum(venders1:x1*c1)+@sum(vg1(i,j):g1(i,j)*z1(i,j))+@sum(goods1:h1*i1)+@sum(vg2(i,j):P2(i,j)*z2(i,j))+@sum(venders2:x2*c2)+@sum(vg2(i,j):g2(i,j)*z2(i,j)+@sum(goods2:h2*i2</font></a>));<br/>@FOR(vg1(i,j):z1(i,j)&lt;=b1(i,j));<br/>@for(vg2(i,j):z2(i,j)&lt;=b2(i,j));</p><p>@for(goods1(j):i1(j)+@sum(goods1(j):z1(i,j)&gt;=m1(j)+1.28o1(j)));<br/>venders1(i):x1(i)=@if(vg1(i,j):z1(i,j)#gt#0,1,0);</p><p>venders2(i):x2(i)=@if(vg2(i,j):z2(i,j)#gt#0,1,0);</p><p>goods2:i2(j)=goods1:i1(j)+@sum(goods2(j):z2(i,j)-m2(j));<br/>end</p><p>这是一个求两阶段规划问题,其中goods2:i2(j)=goods1:i1(j)+@sum(goods2(j):z2(i,j)-m2(j));是状态转移方程,由于本人刚接触lingo&nbsp;所以用的方法比较笨拙,出现错误也不知如何修改,哪位高手能指点一下吗</p>
发表于 2007-4-7 04:17:50 | 显示全部楼层
多谢多谢多谢多谢多谢多谢多谢
发表于 2007-4-12 17:33:13 | 显示全部楼层
model:<br/>&nbsp; sets:<br/>&nbsp; distri/D1..D22/uanty,Time;<br/>&nbsp; order/j1..j22/;<br/>&nbsp; links(distri,order): cost,volume;<br/>endsets<br/>&nbsp; !目标函数;<br/>&nbsp; <a href="mailto:min=@sum(links">min=@sum(links</a>: cost*volume);<br/>&nbsp; !约束条件<br/>&nbsp; @for(distri(I):<br/>&nbsp;&nbsp;&nbsp; @sum(order(J): volume(I,J))=1;<br/>&nbsp; );<br/>&nbsp; !约束条件<br/>&nbsp; @for(order(J):<br/>&nbsp;&nbsp;&nbsp; @sum(distri(I): volume(I,J))=1;<br/>&nbsp; );<br/>&nbsp; !约束条件;&nbsp;&nbsp; <br/>&nbsp;&nbsp; @for(distri(I):<br/>&nbsp;&nbsp;&nbsp; @sum(distri(I):<br/>&nbsp;&nbsp;&nbsp; volume(I,J)*Time(I) )&lt;=240;<br/>&nbsp; !约束条件;&nbsp;&nbsp; <br/>&nbsp;&nbsp; @for(distri(I):<br/>&nbsp;&nbsp;&nbsp; @sum(distri(I):<br/>&nbsp;&nbsp; volume(I,J)* Quanty(I) )&lt;=3.36;&nbsp; <br/>data: <br/>&nbsp; cost=0.057 0.041 0.038 0.028 0.037 0.048 0.032 0.058 0.037 0.037 0.052 0.040 0.024 0.027 0.033 0.031 0.043 0.034 0.041 0.045 0.025 0.0314;<br/>&nbsp;&nbsp; Quanty=0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.1 0.3 0.2 0.3 0.3 0.3 0.3 0.3 0.2 0.3;&nbsp; <br/>&nbsp;&nbsp; Time=7.1003 4.5130 4.7333 4.8333 7.1 9.4667 4.513 30.7667 5.2067 4.0396 17.293 7.353 69.2111 5.9074 15.9111 10.4133 33.2963&nbsp; 13.5193 15.6200 21.2815&nbsp; 4.26 3.0074 ;<br/>enddata<br/>end<br/>
发表于 2007-4-12 17:34:21 | 显示全部楼层
<p>高手们帮忙看看上面的程序啊,我的QQ602811504多谢了</p>
发表于 2007-4-16 21:42:25 | 显示全部楼层
<p>谢谢楼主!</p><p>aquietfish@yahoo.com.cn</p>
发表于 2007-4-18 03:17:01 | 显示全部楼层
<p>版主&nbsp; 谢谢了哈</p><p>我的油箱是&nbsp;&nbsp; <a href="mailto:myengel_65@163.com">myengel_65@163.com</a></p><p>谢谢哈</p>
发表于 2007-6-1 13:55:33 | 显示全部楼层
谢谢楼主,m-l139@163.com
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