这是自动化车床管理中一段小程序，刚开始我是对U从300到400以十为步进循环，发现T1值在300时是四点几，到后来都是五点几。
而如果我单取U为350时，T1值是4.6....，根本没达到5。
这下我就觉得奇怪了，然而更怪的是如果我把m=(n+1)/2变个位置，结果就是T1＝5.2030。
真不知到底怎么搞得，还请大侠帮忙。
syms x n u
gzjl=[459,362,624,542,509,584,433 748,815,505,612,452,434,982,640,742,565,706,593,680,926,653,164,487,734,608,428,1153,593,844,527,552,513,781,474,388,824,538,862,659,775,859,755,649,697,515,628,954,771,609,402,960,885,610,292,837,473,677,358,638,699,634,555,570,84,416,606,1062,484,120,447,654,564,339,280,246,687,539,790,581,621,724,531,512,577,496,468,499,544,645,764,558,378,765,666,763,217,715,310,851];
q=sum(gzjl)/100
det=sqrt(sum((gzjl-q).^2)/99)
t=10;f=200;d=3000;k=1000;
ff=exp(-(x-q)^2/(2*det^2))/(det*sqrt(2*pi));
u=350;
F=int(ff,0,u);a=(int(x*ff,0,u)+u*(1-F))/F;
c=1/(1/14400+1/a);
n=sqrt(2*c*t/f);
m=(n+1)/2;
T=t/n+k/u+(d+m*f)/c;
T1=double(T)
n=double(n)
把m=(n+1)/2; 调到 F=int(ff,0,u);a=(int(x*ff,0,u)+u*(1-F))/F;前
syms x n u
gzjl=[459,362,624,542,509,584,433 748,815,505,612,452,434,982,640,742,565,706,593,680,926,653,164,487,734,608,428,1153,593,844,527,552,513,781,474,388,824,538,862,659,775,859,755,649,697,515,628,954,771,609,402,960,885,610,292,837,473,677,358,638,699,634,555,570,84,416,606,1062,484,120,447,654,564,339,280,246,687,539,790,581,621,724,531,512,577,496,468,499,544,645,764,558,378,765,666,763,217,715,310,851];
q=sum(gzjl)/100
det=sqrt(sum((gzjl-q).^2)/99)
t=10;f=200;d=3000;k=1000;
ff=exp(-(x-q)^2/(2*det^2))/(det*sqrt(2*pi));
u=350;
m=(n+1)/2;
F=int(ff,0,u);a=(int(x*ff,0,u)+u*(1-F))/F;
c=1/(1/14400+1/a);
n=sqrt(2*c*t/f);
T=t/n+k/u+(d+m*f)/c;
T1=double(T)
n=double(n)
运行一下，T1的结果不同。
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发表于 2003-8-23 19:44:35
发表于 2003-8-23 21:59:55