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求2001年书摸竞赛血管切片三维重建的matlab程序!!!

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发表于 2004-6-4 19:10:24 | 显示全部楼层 |阅读模式
<>看了这里写的论文,都有一个根据100张切片重构出三维实体的图片,</P>
<>可是我不知道用matlab怎么才能购造出来,那位高人能不能给我写出用</P>
<>matlab重构的程序啊???</P>
<P>急!!!!!!!!!!!!!!!!!!!!!!</P>
<P>谢谢啊!</P>
发表于 2004-7-26 05:59:30 | 显示全部楼层
我也想知道啊
发表于 2004-7-26 07:00:49 | 显示全部楼层
这是我们老师powerpoint讲稿里粘贴过来的,大家自己看看吧<DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><B><FONT size=4>如何读入一个数字图象,即如何由bmp图象文件(或其它格式的图象文件)得到象素矩阵? </FONT></B></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><FONT size=4><B> <FONT size=4> </FONT><FONT size=4>MATLAB</FONT></B></FONT><FONT size=4><B>函数</B><B>imread ( )</B><B>:</B><B> m=imread(</B><B>‘</B><B>0.bmp</B><B>’</B><B>) </B></FONT></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>或把图象序列转换为三维数组 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>for b=0:99 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>   m(:,:,b+1)=imread([int2str(b),'.bmp']); </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>end </FONT></B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><FONT size=4> </FONT><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>何谓边界点? </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>   四邻域的概念  找边界点坐标的算法 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>也可用MATLAB函数:edge() </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><FONT size=4><B>如:</B><B>m=imread(</B><B>‘</B><B>0.bmp</B><B>’</B><B>)</B><B>;</B><B>bw=edge(m, </B><B>‘</B><B>sobel</B><B>’</B><B>) </B></FONT></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>3)最大内切圆的圆心和半径须取小数和整数有区别吗? </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><B><FONT size=4>4)取整方法:四舍五入(round),向上取整(ceil),向下取整(floor) </FONT></B></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><FONT size=4> </FONT><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>如何由切片图叠合作出血管的立体图? </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>方法1:利用plot3() </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>for b=0:99 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>   m1=imread([int2str(b),'.bmp']); </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>   m(:,:,b+1)=edge(m1,'sobel'); </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>end </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>for k=0:99 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>   for i=1:512 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>      for j=1:512 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>         if (m(i,j,k+1)==1) </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>             plot3(i,j,k+1,'b-.');hold on </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>end,end,end,end </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>rotate3d,hold off </FONT></B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><FONT size=4> </FONT><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>方法2:利用patch() </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>for b=0:99 </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>m(:,:,b+1)=[imread([int2str(b),'.bmp'],'bmp')]'; </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>end </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>m1=m(1:4:512,1:4:512,; </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>for i=1:size(m1,1) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>    for j=1:size(m1,2) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>        for k=1:size(m1,3) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>            if m1(i,j,k)==0 </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>                m1(i, j, k)=88; </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>            else </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>                m1(i,j,k)=0; </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>end, end, end,end </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>ms=smooth3(m1); </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>hiso=patch(isosurface(ms,5),'FaceColor',[1,.75,.65],'EdgeColor','none'); </B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>hcap=patch(isocaps(m1,5),'FaceColor','interp','EdgeColor','none'); </B></NOBR><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>colormap('default') </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>view(45,30), axis tight </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>grid </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>daspect([1,1,.4]) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>lightangle(45,30); lighting phong </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>isonormals(ms, hiso) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>set(hcap,'AmbientStrength',.6) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>set(hiso,'SpecularColorReflectance',0,'SpecularExponent',50) </B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>rotate3d</B><B> </B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV>
发表于 2004-8-31 07:35:20 | 显示全部楼层
广西大学学报上黄新民有一篇从中轴线数据建立三维图象的论文
发表于 2004-9-18 06:52:13 | 显示全部楼层
好啊
发表于 2004-9-18 21:46:08 | 显示全部楼层
ooooooo
发表于 2010-7-21 10:50:17 | 显示全部楼层
谢谢分享哈
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