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急!!!!!!!!!!

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发表于 2005-8-30 23:41:27 | 显示全部楼层 |阅读模式
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<TD  vAlign=top width=* height="100%"><IMG src="http://www.shumo.com/bbs/Skins/Default/topicface/face1.gif" align=absMiddle border=0> <B>工件检测问题</B><BR>
< align=left>请高手给点思路:</P>
< align=left>       </P>
<>某工件为圆形<FONT face="Times New Roman">, </FONT>半径为<ST1:CHMETCNV UnitName="mm" SourceValue="10" HasSpace="False" Negative="False" NumberType="1" TCSC="0" w:st="on"><FONT face="Times New Roman">10mm</FONT></ST1:CHMETCNV><V:SHAPETYPE><FONT face="Times New Roman"> <V:STROKE joinstyle="miter"></V:STROKE><V:FORMULAS><V:F eqn="if lineDrawn pixelLineWidth 0"></V:F><V:F eqn="sum @0 1 0"></V:F><V:F eqn="sum 0 0 @1"></V:F><V:F eqn="prod @2 1 2"></V:F><V:F eqn="prod @3 21600 pixelWidth"></V:F><V:F eqn="prod @3 21600 pixelHeight"></V:F><V:F eqn="sum @0 0 1"></V:F><V:F eqn="prod @6 1 2"></V:F><V:F eqn="prod @7 21600 pixelWidth"></V:F><V:F eqn="sum @8 21600 0"></V:F><V:F eqn="prod @7 21600 pixelHeight"></V:F><V:F eqn="sum @10 21600 0"></V:F></V:FORMULAS><VATH connecttype="rect" extrusionok="f" gradientshapeok="t"></VATH><LOCK v:ext="edit" aspectratio="t"></LOCK></FONT></V:SHAPETYPE><V:SHAPE><V:IMAGEDATA></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman"><ST1:CHMETCNV UnitName="mm" SourceValue=".1" HasSpace="False" Negative="False" NumberType="1" TCSC="0" w:st="on">0.1mm</ST1:CHMETCNV>, </FONT>超出此范围即为次品<FONT face="Times New Roman">. </FONT>测量仪器自动在每个工件的圆周上测量<FONT face="Times New Roman">36</FONT>个数据<FONT face="Times New Roman">. </FONT>假定测量出的二维数据<FONT face="Times New Roman"> (</FONT><V:SHAPE><FONT face="Times New Roman"> <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT face="Times New Roman">, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">) </FONT>是足够精确的<FONT face="Times New Roman">, </FONT>要求建立一个合理的检验正<FONT face="Times New Roman">/</FONT>次品的模型<FONT face="Times New Roman">, </FONT>对每个工件的<FONT face="Times New Roman">36</FONT>个数据进行计算后给出判断。</P>
<P>
<P><FONT face="Times New Roman" size=3></FONT></P><BR>
<P>下面是<FONT face="Times New Roman">5</FONT>个工件的测量文件<FONT face="Times New Roman">, </FONT>存放顺序为</P><FONT face="Times New Roman">
<P align=center><FONT size=3>(</FONT><FONT size=3>(</FONT><V:SHAPE><FONT size=3> x11<V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT size=3>y11</FONT></V:IMAGEDATA></V:SHAPE><FONT size=3>)</FONT><FONT size=3>,</FONT><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x12 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE>
<P><V:IMAGEDATA><FONT size=3></FONT></V:IMAGEDATA></P>
<P><V:IMAGEDATA><FONT size=3>y12</FONT></V:IMAGEDATA></P></V:SHAPE><FONT size=3>)</FONT><FONT size=3>,……,</FONT><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x1,36 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT size=3>y1,36</FONT></V:IMAGEDATA></V:SHAPE><FONT size=3>)</FONT>
<br>
<P align=center><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x21 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT size=3>y21</FONT></V:IMAGEDATA></V:SHAPE><FONT size=3>)</FONT><FONT size=3>,</FONT><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x22 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT size=3>y22</FONT></V:IMAGEDATA></V:SHAPE><FONT size=3>)</FONT><FONT size=3>,……,</FONT><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x2,36 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT size=3>y2,36</FONT></V:IMAGEDATA></V:SHAPE><FONT size=3>)</FONT></P>
<P align=center><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x31 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT size=3>y31</FONT></V:IMAGEDATA></V:SHAPE><FONT size=3>)</FONT><FONT size=3>,</FONT><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x32 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT size=3>y32</FONT></V:IMAGEDATA></V:SHAPE><FONT size=3>)</FONT><FONT size=3>,……,</FONT><FONT size=3>(</FONT><V:SHAPE><FONT size=3>x3,36 <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT size=3>, y3,36)</FONT></FONT></P>
<P align=center><FONT face="Times New Roman" size=3>(</FONT><V:SHAPE><FONT size=3><FONT face="Times New Roman">x41 <V:IMAGEDATA></V:IMAGEDATA></FONT></FONT></V:SHAPE><FONT face="Times New Roman" size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman" size=3>y41</FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman" size=3>)</FONT><FONT size=3>,</FONT><FONT face="Times New Roman" size=3>(</FONT><V:SHAPE><FONT size=3><FONT face="Times New Roman">x42 <V:IMAGEDATA></V:IMAGEDATA></FONT></FONT></V:SHAPE><FONT face="Times New Roman" size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman" size=3>y42</FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman" size=3>)</FONT><FONT size=3>,……,</FONT><FONT face="Times New Roman" size=3>(</FONT><V:SHAPE><FONT size=3><FONT face="Times New Roman">x4,36 <V:IMAGEDATA></V:IMAGEDATA></FONT></FONT></V:SHAPE><FONT face="Times New Roman" size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman" size=3>y4,36</FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman" size=3>)</FONT></P>
<P align=center><FONT face="Times New Roman" size=3>(</FONT><V:SHAPE><FONT size=3><FONT face="Times New Roman">x51 <V:IMAGEDATA></V:IMAGEDATA></FONT></FONT></V:SHAPE><FONT face="Times New Roman" size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman" size=3>y51</FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman" size=3>)</FONT><FONT size=3>,</FONT><FONT face="Times New Roman" size=3>(</FONT><V:SHAPE><FONT size=3><FONT face="Times New Roman">x52 <V:IMAGEDATA></V:IMAGEDATA></FONT></FONT></V:SHAPE><FONT face="Times New Roman" size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman" size=3>y52</FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman" size=3>)</FONT><FONT size=3>,……,</FONT><FONT face="Times New Roman" size=3>(</FONT><V:SHAPE><FONT size=3><FONT face="Times New Roman">x5,36 <V:IMAGEDATA></V:IMAGEDATA></FONT></FONT></V:SHAPE><FONT face="Times New Roman" size=3>, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman" size=3>y5,36</FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman" size=3>)</FONT></P>
<P align=center><FONT face="Times New Roman" size=3></FONT></P>
<P align=center>其中<FONT face="Times New Roman">(xi</FONT><V:SHAPE><FONT face="Times New Roman"> j<V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><FONT face="Times New Roman">,yij </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">)</FONT>表示第<V:SHAPE><FONT face="Times New Roman"> i<V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE>个工件第<V:SHAPE><FONT face="Times New Roman"> j<V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE>个测量数据<FONT face="Times New Roman"> (1.</FONT><V:SHAPE><FONT face="Times New Roman"> <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">5, 1</FONT><V:SHAPE><FONT face="Times New Roman"> <V:IMAGEDATA></V:IMAGEDATA></FONT></V:SHAPE><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">36)</FONT>。如第一个工件中<FONT face="Times New Roman"> </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 31.270, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 34.290, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 31.227, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 36.554, </FONT>……<FONT face="Times New Roman">, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 30.964, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 31.517, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 31.105, </FONT><V:SHAPE><V:IMAGEDATA><FONT face="Times New Roman"></FONT></V:IMAGEDATA></V:SHAPE><FONT face="Times New Roman">= 32.743</FONT>。</P>
<P align=left></P><BR></TD></TR></TABLE>
发表于 2005-8-31 00:08:42 | 显示全部楼层
不急慢慢来
发表于 2005-8-31 00:44:53 | 显示全部楼层
<>这用MATLAB不是很容易吗??</P>
 楼主| 发表于 2005-8-31 01:28:51 | 显示全部楼层
<>不会啊?</P>
发表于 2005-9-4 00:37:14 | 显示全部楼层
<>我认为这个可以用OFFICE 2005的回归分析来做 </P>
<>也可以用EVIEW来做</P>
<>很简单的 </P>
发表于 2005-9-4 07:53:31 | 显示全部楼层
想知道,个人感觉算出每个数的均值,落在(0.1,10)即为正品[em04]
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