求2001年书摸竞赛血管切片三维重建的matlab程序！！！

adonis8212 发表于 2004-6-4 19:10:24

<P>看了这里写的论文，都有一个根据100张切片重构出三维实体的图片，</P>
<P>可是我不知道用matlab怎么才能购造出来，那位高人能不能给我写出用</P>
<P>matlab重构的程序啊？？？</P>
<P>急！！！！！！！！！！！！！！！！！！！！！！</P>
<P>谢谢啊！</P>

艾谨发表于 2004-7-26 05:59:30

我也想知道啊

wangyantao1982 发表于 2004-7-26 07:00:49

这是我们老师powerpoint讲稿里粘贴过来的，大家自己看看吧<DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><B><FONT size=4>如何读入一个数字图象，即如何由bmp图象文件（或其它格式的图象文件）得到象素矩阵？ </FONT></B></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><FONT size=4><B> <FONT size=4> </FONT><FONT size=4>MATLAB</FONT></B></FONT><FONT size=4><B>函数</B><B>imread ( )</B><B>：</B><B> m=imread(</B><B>‘</B><B>0.bmp</B><B>’</B><B>) </B></FONT></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>或把图象序列转换为三维数组 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>for b=0:99 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> m(:,:,b+1)=imread(); </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>end </FONT></B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><FONT size=4> </FONT><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>何谓边界点？ </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> 四邻域的概念找边界点坐标的算法 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>也可用MATLAB函数:edge() </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><FONT size=4><B>如：</B><B>m=imread(</B><B>‘</B><B>0.bmp</B><B>’</B><B>)</B><B>；</B><B>bw=edge(m, </B><B>‘</B><B>sobel</B><B>’</B><B>) </B></FONT></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>3）最大内切圆的圆心和半径须取小数和整数有区别吗？ </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><B><FONT size=4>4）取整方法：四舍五入（round)，向上取整(ceil)，向下取整(floor) </FONT></B></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><FONT size=4> </FONT><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>如何由切片图叠合作出血管的立体图？ </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>方法1：利用plot3() </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>for b=0:99 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> m1=imread(); </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> m(:,:,b+1)=edge(m1,'sobel'); </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>end </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>for k=0:99 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> for i=1:512 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> for j=1:512 </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> if (m(i,j,k+1)==1) </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4> plot3(i,j,k+1,'b-.');hold on </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>end,end,end,end </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-160 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>rotate3d，hold off </FONT></B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><FONT size=4> </FONT><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B><FONT size=4>方法2：利用patch() </FONT></B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>for b=0:99 </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>m(:,:,b+1)=,'bmp')]'; </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>end </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>m1=m(1:4:512,1:4:512,:); </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>for i=1:size(m1,1) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B> for j=1:size(m1,2) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B> for k=1:size(m1,3) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B> if m1(i,j,k)==0 </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B> m1(i, j, k)=88; </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B> else </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B> m1(i,j,k)=0; </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>end, end, end,end </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>ms=smooth3(m1); </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>hiso=patch(isosurface(ms,5),'FaceColor',,'EdgeColor','none'); </B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>hcap=patch(isocaps(m1,5),'FaceColor','interp','EdgeColor','none'); </B></NOBR><DIV class=O v:shape="_x0000_s1026"><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>colormap('default') </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>view(45,30), axis tight </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>grid </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>daspect() </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>lightangle(45,30); lighting phong </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>isonormals(ms, hiso) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>set(hcap,'AmbientStrength',.6) </B></NOBR></DIV><DIV justify; mso-line-spacing: '-144 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>set(hiso,'SpecularColorReflectance',0,'SpecularExponent',50) </B></NOBR></DIV><DIV justify; mso-line-spacing: '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"><NOBR><B>rotate3d</B><B> </B></NOBR></DIV><DIV '100 50 0'; mso-char-wrap: 1; mso-kinsoku-overflow: 1"></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV>

hhhhhhhhhh 发表于 2004-8-31 07:35:20

广西大学学报上黄新民有一篇从中轴线数据建立三维图象的论文

zimen 发表于 2004-9-18 06:52:13

好啊

wujin304 发表于 2004-9-18 21:46:08

ooooooo

daijiangnan 发表于 2010-7-21 10:50:17

谢谢分享哈

页: [1]

数模论坛's Archiver

求2001年书摸竞赛血管切片三维重建的matlab程序！！！